How do you evaluate the expression 6x + 2y + 5y + 7 +y if x=8, y=1?

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Answer 1 · 2018-03-04T23:39:17

See a solution process below:

For each occurrence of $x$ $color(red)(x)$ substitute $8$ $color(red)(8)$

And, For each occurrence of $y$ $color(blue)(y)$ substitute $1$ $color(blue)(1)$

$6 x + 2 y + 5 y + 7 + y$ $6color(red)(x) + 2color(blue)(y) + 5color(blue)(y) + 7 + color(blue)(y)$ becomes:

$(6 \times 8) + (2 \times 1) + (5 \times 1) + 7 + 1$ $(6 xx color(red)(8)) + (2 xx color(blue)(1)) + (5 xx color(blue)(1)) + 7 + color(blue)(1)$

$48 + 2 + 5 + 7 + 1$ $48 + 2 + 5 + 7 + 1$

$50 + 12 + 1$ $50 + 12 + 1$

$62 + 1$ $62 + 1$

$63$ $63$