How do you evaluate the following expression when x = 3 and y = 4: for ${(y - x)}^{2}$ $(y - x)^2$ ?

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How do you evaluate the following expression when x = 3 and y = 4: for ${(y - x)}^{2}$ $(y - x)^2$ ?

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Answer 1 · 2015-09-09T14:10:45

${(y - x)}^{2}$ $(y-x)^2$ at $x = 3$ $x=3$ and $y = 4$ $y=4$ is $1$ $1$ .

Explanation:

To evaluate an expression means to get its value when you plug in values for variables.

You're given the values $x = 3$ $x=3$ and $y = 4$ $y=4$ .
To evaluate ${(y - x)}^{2}$ $(y-x)^2$ for those values, you should plug in the values, meaning you should replace all $x$ $x$ s with the value $3$ $3$ and all $y$ $y$ s with the value $4$ $4$ .

${(y - x)}^{2}$ $(y-x)^2$
$\Rightarrow {(4 - 3)}^{2}$ $=> (4-3)^2$

Now we can simplify the expression.

${(4 - 3)}^{2}$ $(4-3)^2$
$= 1^{2}$ $=1^2$
$= 1$ $=1$

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How do you evaluate the following expression when x = 3 and y = 4: for ${(y - x)}^{2}$ $(y - x)^2$ ?

1 Answer

Explanation:

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How do you evaluate the following expression when x = 3 and y = 4: for (y−x)2(y - x)^2?

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