How do you evaluate the function $g (x) = 5000 (2^{x})$ $g(x)=5000(2^x)$ at the value of $x = - 1.5$ $x=-1.5$ ?

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Answer 1 · 2018-02-13T03:49:19

$g (x) \approx 1767.77$ $g(x) ~~ 1767.77$

You just plug in $x = - 1.5$ $x=-1.5$ into the function.

$g (x) = 5000 (2^{- 1.5})$ $g(x) = 5000(2^-1.5)$

$g (x) \approx 5000 (0.35355)$ $g(x) ~~ 5000(0.35355)$

$g (x) \approx 1767.77$ $g(x) ~~ 1767.77$

By the way, the $\approx$ $~~$ sign just means that it's around that value (not exact).

Hope this helps!

How do you evaluate the function g(x)=5000(2^x)g(x)=5000(2x)g(x)=5000(2^x) at the value of x=-1.5x=−1.5x=-1.5?