How do you evaluate the integral #int e^(2x)sqrt(1+e^(2x))#?
1 Answer
Mar 1, 2017
Explanation:
Let
#int e^(2x)sqrt(u) * (du)/(2e^(2x))#
#1/2int sqrt(u) du#
#1/2(2/3u^(3/2)) + C#
#1/3u^(3/2) + C#
#1/3(1 + e^(2x))^(3/2) + C#
Hopefully this helps!