How do you evaluate $\frac{- z^{2} (1 - 2 x)}{y - x}$ $(-z^2(1-2x))/(y-x)$ given x=-2, y=-3, z=5?

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Answer 1 · 2016-11-03T22:48:36

$75$ $75$

Substituting the given values gives:

$\frac{- (5^{2}) (1 - 2 (- 2))}{- 3 - - 2} \Rightarrow$ $(-(5^2)(1 - 2(-2)))/(-3 - -2) =>$

$\frac{- 25 (1 - - 2)}{- 1} \Rightarrow$ $(-25(1 - -2))/-1 =>$

$\frac{- 25 \cdot 3}{- 1} \Rightarrow$ $(-25 * 3)/-1 =>$

$\frac{- 75}{- 1} \Rightarrow$ $(-75)/-1 =>$

$75$ $75$

How do you evaluate −z2(1−2x)y−x(-z^2(1-2x))/(y-x) given x=-2, y=-3, z=5?