How do you expand #5(2y-3)#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer smendyka Dec 12, 2016 #10y - 15# Explanation: To expand this expression you need to distribute the #5# across the terms within the parenthesis" #5(2y - 3) -> (5*2y) - (5*3) -> 10y - 15# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 6582 views around the world You can reuse this answer Creative Commons License