How do you expand #(x^4-y^3)^3#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Gerardina C. Jul 6, 2016 #x^12-3x^8y^3+3x^4y^6-y^9# Explanation: Since #(a+b)^3=a^3+3a^2b+3ab^2+b^3# you have: #(x^4-y^3)^3=(x^4)^3+3(x^4)^2(-y^3)+3(x^4)(-y^3)^2+(-y^3)^3# that's #x^12-3x^8y^3+3x^4y^6-y^9# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 1395 views around the world You can reuse this answer Creative Commons License