How do you express the complex number in trigonometric form: #6#?

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Answer 1 · 2018-06-08T08:01:09

See explanation.

The number #6# lies on a positive part of real axis, so the angle is #0# and the module is #6#, so the trigonometric form of #6# is:

#6=6*(cos0^o + isin0^o)# ##