How do you factor $12 a^{2} - 24 a^{3}$ $12a^2 - 24a^3$ ?

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How do you factor $12 a^{2} - 24 a^{3}$ $12a^2 - 24a^3$ ?

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Answer 1 · 2016-07-12T11:59:46

$12 a^{2} (1 - 2 a)$ $12a^2(1-2a)$

Explanation:

Let's take out common factors. First, we need to list out the factors.

$12 a^{2} = 12 \times a \times a$ $12a^2 = 12timesatimesa$

$24 a^{3} = 24 \times a \times a \times a$ $24a^3= 24timesatimesatimesa$

Let look at what we can take out. Well $12$ $12$ is a factor of both $12$ $12$ and $24$ $24$ , so let's pull out a $12$ $12$ . We also see that both terms have at least two $a$ $a$ s, so let's pull out two $a$ $a$ s.

$12 a^{2} (1 - 2 a)$ $12a^2(1-2a)$ or $12 (a) (a) (1 - 2 a)$ $12(a)(a)(1-2a)$

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How do you factor $12 a^{2} - 24 a^{3}$ $12a^2 - 24a^3$ ?

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