How do you factor $18m² n^4-12m² n^3+24m² n²$ ?

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Answer 1 · 2015-06-07T21:52:34

$18m^2n^4-12m^2n^3+24m^2n^2$

$=6m^2n^2(3n^2-2n+4)$

$(3n^2-2n+4)$ has no simpler linear factors since it's discriminant is negative:

$Delta(3n^2-2n+4) = (-2)^2 - (4xx3xx4)$

$= 4 - 48 = -44$

How do you factor 18m² n^4-12m² n^3+24m² n²18m² n^4-12m² n^3+24m² n²?