How do you factor $28 a^{3} b^{4} + 20 a^{2} b^{2} - 16 a b^{3}$ $28a^3b^4+20a^2b^2-16ab^3$ ?

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Answer 1 · 2017-01-03T20:03:18

Let's first take out the numbers

$= 4 \times (7 a^{3} b^{4} + 5 a^{2} b^{2} - 4 a b^{3})$ $=4xx(7a^3b^4+5a^2b^2-4ab^3)$

From every term we can take out $a b^{2}$ $ab^2$
$= 4 a b^{2} (7 a^{2} b^{2} + 5 a - 4 b)$ $=4ab^2(7a^2b^2+5a-4b)$

How do you factor 28a3b4+20a2b2−16ab328a^3b^4+20a^2b^2-16ab^3?