How do you factor $2x^2- 18$ ?

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Answer 1 · 2015-09-28T21:43:23

The answer is $2(x+3)(x-3)$ .

$2x^2-18$

Factor out the GCF $2$ .

$2(x^2-9)$

$x^2-9$ fits the form $a^2-b^2$ , where $a=x and b=3$ .

Rewrite the expression.

$2(x^2-3^2)$

$a^2-b^2=(a+b)(a-b)$

$2(x+3)(x-3)$

How do you factor 2x^2- 182x^2- 18?