How do you factor 3bc2b10+15c?

1 Answer
Jan 20, 2017

3bc2b10+15c=(b+5)(3c2)

Explanation:

This quadrinomial factors by grouping (at least once we swap a couple of the terms around)...

3bc2b10+15c=3bc2b+15c10

3bc2b10+15c=(3bc2b)+(15c10)

3bc2b10+15c=b(3c2)+5(3c2)

3bc2b10+15c=(b+5)(3c2)