How do you factor $3v^3 + 4v - 2v^2$ ?

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Answer 1 · 2018-06-02T07:33:14

$=v(3v^2+4-2v)$

$3v^3-4v -2v^2$

The only factor that all the terms have in common is $v$

Divide $v$ from each term

$=v(3v^2+4-2v)$

There are now two factors.

How do you factor 3v^3 + 4v - 2v^2 3v^3 + 4v - 2v^2 ?