How do you factor $3 x^{2} + 6 x + x + 2$ $3x^2+6x+x+2$ ?

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How do you factor $3 x^{2} + 6 x + x + 2$ $3x^2+6x+x+2$ ?

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Answer 1 · 2017-04-26T11:04:26

$(x + 2) (3 x + 1)$ $(x+2)(3x+1)$

Explanation:

Your immediate question should be: why have they chosen this format for the question?

Notice that they split the terms. So does this imply a repeat of some form?

Notice that for $3 x^{2} + 6 x \to 3 x (x + 2)$ $3x^2+6x->3x(x+2)$ and the $x + 2$ $x+2$ is the right hand split part. So we write:

$3 x^{2} + 6 x + x + 2 \to (3 x^{2} + 6 x) + (x + 2)$ $3x^2+6x+x+2" "->" "(3x^2+6x)+(x+2)$
$3 x (x + 2) . . + 1 (x + 2)$ $" "3x(x+2)color(white)(..)+1(x+2)$

Factor out the $(x + 2)$ $(x+2)$ giving

$(x + 2) (3 x + 1)$ $" "(x+2)(3x+1)$

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How do you factor $3 x^{2} + 6 x + x + 2$ $3x^2+6x+x+2$ ?

1 Answer

Explanation:

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How do you factor $3 x^{2} + 6 x + x + 2$ $3x^2+6x+x+2$ ?