How do you factor $3 x^{3} + 21 x^{2} + 30 x$ $3x^3+21x^2+30x$ ?

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How do you factor $3 x^{3} + 21 x^{2} + 30 x$ $3x^3+21x^2+30x$ ?

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Answer 1 · 2016-05-06T16:17:21

$3 x^{3} + 21 x^{2} + 30 x = 3 x (x + 2) (x + 5)$ $3x^3+21x^2+30x=3x(x+2)(x+5)$

Explanation:

First notice that all of the terms are divisible by $3 x$ $3x$ , so separate that out as a factor. Then note that $7 = 2 + 5$ $7 = 2+5$ and $10 = 2 \times 5$ $10 = 2xx5$ , so use that to factor the remaining quadratic:

$3 x^{3} + 21 x^{2} + 30 x = 3 x (x^{2} + 7 x + 10) = 3 x (x + 2) (x + 5)$ $3x^3+21x^2+30x=3x(x^2+7x+10)=3x(x+2)(x+5)$

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How do you factor $3 x^{3} + 21 x^{2} + 30 x$ $3x^3+21x^2+30x$ ?

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How do you factor 3x3+21x2+30x 3x^3+21x^2+30x?

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How do you factor $3 x^{3} + 21 x^{2} + 30 x$ $3x^3+21x^2+30x$ ?