How do you factor: $3x^3 - 9x^2$ ?

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Answer 1 · 2018-04-02T13:19:30

$3x^2(x-3)$

When factorising, take out ALL of the common factors

ie $3 times x times x times x - 9 times x times x$

you notice that the common factors are 3 and 2 "x"
so you can factorise it to:
$3x^2(x-3)$

How do you factor: 3x^3 - 9x^23x^3 - 9x^2?