Question

How do you factor: `3y - 6x + 4xy - 2y^2`?

Answer 1

`(y-2x)(3-2y)`

Explanation:

Group the terms in 'pairs'

That is `[3y-6x]+[4xy-2y^2]`

now factorise each 'pair' by taking out a `color(blue)"common factor"`

`rArrcolor(red)(3)(y-2x)color(red)(-2y)(y-2x)`

We now have a `color(blue)"common factor"` of (y - 2x)

`rArr(y-2x)(color(red)(3-2y))`

`rArr3y-6x+4xy-2y^2=(y-2x)(3-2y)`