Extracting the obvious common factor of 3x from 42x^3+51x^2-18x gives
color(white)("XXX")3x(14x^2+17x-6)
There are several ways of factoring (14x^2+17x-6)
One way is to look for factors (color(blue)(a)*color(green)(b))of 14 and (color(cyan)(c)*color(orange)(d)) of (-6)
such that color(blue)(a)color(orange)(d)-color(green)(b)color(cyan)(c)=17
in order to generate the factors (color(blue)(a)x+color(cyan)(c))(color(green)(b)x+color(orange)(d))
Table of color(blue)(a)color(orange)(d)-color(green)(b)color(cyan)(c)
{:
("factors of " 14 (axxb)":"," | ",(color(blue)(1) * color(green)(14))," | ",(color(blue)(2) * color(green)(7))," | ",(color(blue)(7) * color(green)(2))," | ",(color(blue)(14) * color(green)(1))),
("----------------------",,"--------------------",,"--------------------",,"--------------------",,"--------------------"),
("factors of "(-6) (cxxd)":"," | ", ," | ", ," | ",," | ", ),
(color(white)("XX")((color(cyan)(-1)) * color(orange)(6))," | ",-14+6=-8," | ", -7+12=5," | ",-2+42=40," | ",-1+84=83),
(color(white)("XX")((color(cyan)(-2)) * color(orange)(3))," | ", -28+3=-25," | ",-14+6=-8," | ",color(red)(-4+21=17)," | ", ". . ." ),
(color(white)("XX")(color(cyan)(2) * (color(orange)(-3)) )," | ",". . ." ," | ", ". . ."," | ",". . ." ," | ", ". . ." ),
(color(white)("XX")(color(cyan)(1) * (color(orange)(-6))) ," | ", ". . ." , " | ", ". . .", " | ",". . ." ," | ", ". . .")
:}
Which gives us the factoring (ax+c)(bx+d)
color(white)("XXX")14x^2+17x-6 = (color(blue)(7)xcolor(cyan)(-2))(color(green)(2)xcolor(orange)(+3))
rArr42x^3+52x^2-18x = (3x)(7x-2)(2x+3)
