How do you factor: $49y^2-4$ ?

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Answer 1 · 2015-12-21T14:57:47

$= color(blue)((7y+2)(7y-2)$

$49y^2-4$

The above expression can be written as:

$49y^2-4 = (7y)^2-2^2$

As per identity

$color(blue)(a^2-b^2=(a+b)(a-b)$

So,
$(7y)^2-2^2= color(blue)((7y+2)(7y-2)$

How do you factor: 49y^2-449y^2-4?