How do you factor $4 x^{2} y^{3} + 6 x y$ $4x^2y^3 + 6xy$ ?

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Answer 1 · 2018-04-17T01:00:57

$2 x y (2 x y^{2} + 3)$ $2xy(2xy^2+3)$

Look for what is common in the two terms:

$4 x^{2} y^{3} + 6 x y$ $4x^2y^3+6xy$

$2 x y (2 x y^{2}) + 2 x y (3)$ $2xy(2xy^2)+2xy(3)$

$2 x y (2 x y^{2} + 3)$ $2xy(2xy^2+3)$

How do you factor 4x2y3+6xy4x^2y^3 + 6xy?