How do you factor $6 - 2 (n + 4)$ $6-2(n+4)$ ?

Question

1517 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-08T01:10:38

$- 2 (n + 1)$ $-2(n+1)$

Distribute the $- 2$ $-2$ throughout the set of parenthesis
$6 - 2 n - 8$ $6-2n-8$

Combine like terms
$6 - 8 = - 2$ $6-8=-2$

So the problem now looks like:
$- 2 n - 2$ $-2n-2$

To factor, you would take out a GCF (Greatest Common Factor)
$- 2 (n + 1)$ $-2(n+1)$

And that is the answer!

How do you factor 6-2(n+4)6−2(n+4)6-2(n+4)?