How do you factor $6 p q^{2} + 7 q r + 5 p q r$ $6pq^2 +7qr + 5pqr$ ?

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Answer 1 · 2018-07-22T22:11:13

$p q (6 q + 5 p r) + 7 q r or 6 p q^{2} + q r (7 + 5 p)$ $pq(6q + 5pr) + 7qr or 6pq^2 + qr(7 + 5p)$

$6 p q^{2} + 7 q r + 5 p q r$ $6pq^2 + 7qr + 5pqr$

By grouping

$(6 p q^{2} + 5 p q r) + 7 q r$ $(6pq^2 + 5pqr) + 7qr$

$p q (6 q + 5 p r) + 7 q r$ $pq(6q + 5pr) + 7qr$

Or

$6 p q^{2} + (7 q r + 5 p q r)$ $6pq^2 + (7qr + 5pqr)$

$6 p q^{2} + q r (7 + 5 p)$ $6pq^2 + qr(7 + 5p)$

How do you factor 6pq2+7qr+5pqr6pq^2 +7qr + 5pqr?