How do you factor $6 x^{2} - 9 x + 10 x - 15$ $6x^2-9x+10x-15$ ?

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Answer 1 · 2018-05-05T11:44:43

$(3 x + 5) (2 x - 3)$ $(3x+5)(2x-3)$

$6 x^{2} - 9 x + 10 x - 15$ $6x^2 - 9x +10x - 15$

by grouping and taking the common factor

rearrange:

$6 x^{2} + 10 x - 9 x - 15$ $color(red)(6x^2 +10x) color(blue)(- 9x - 15)$

from the red terms take $2 x$ $2x$ common factor
and the blue terms take $- 3$ $-3$ common factor

$2 x (3 x + 5) - 3 (3 x + 5)$ $color(red)(2x)(3x+5)color(blue)(-3)(3x+5)$

now you can take $(3 x + 5)$ $(3x+5)$ as a common factor from both terms

$(3 x + 5) (2 x - 3)$ $(3x+5)(2x-3)$

Answer 2 · 2018-05-05T11:48:01

$6 x^{2} - 9 x + 10 x - 15 = (2 x - 3) (3 x + 5)$ $6x^2-9x+10x-15=color(blue)((2x-3)(3x+5)$

Factor:

$6 x^{2} - 9 x + 10 x - 15$ $6x^2-9x+10x-15$

Factor out the common terms in the first two terms and the second two terms.

$3 x (2 x - 3) + 5 (2 x - 3)$ $3x(2x-3)+5(2x-3)$

Factor out the common term $2 x - 3$ $2x-3$ .

$(2 x - 3) (3 x + 5)$ $(2x-3)(3x+5)$

How do you factor 6x^2-9x+10x-156x2−9x+10x−156x^2-9x+10x-15?