What are the factors of $2 m^{3} + 3 m^{2} + 4 m + 6$ $2m^3+3m^2+4m+6$ ?

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Answer 1 · 2014-11-09T17:12:57

$2 m^{3} + 3 m^{2} + 4 m + 6$ $2m^3+3m^2+4m+6$

by factoring $m^{2}$ $m^2$ out of the first two terms and $2$ $2$ out of the last two terms,

$= m^{2} (2 m + 3) + 2 (2 m + 3)$ $=m^2(2m+3)+2(2m+3)$

by factoring out $2 m + 3$ $2m+3$ ,

$= (m^{2} + 2) (2 m + 3)$ $=(m^2+2)(2m+3)$

Hence, its factors are $(m^{2} + 2)$ $(m^2+2)$ and $(2 m + 3)$ $(2m+3)$ .

I hope that this was helpful.

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