1-Find the greatest number they have in common first.
Looking at the expression, there are three numbers: 3, 6, 93,6,9. The GCF (greatest common factor) of these is 33. Then we look at the greatest variable they have in common. There is only one variable, xx. However, the 99 does not have any xx attached to it, therefore we cannot factor out an xx.
2-Now we have to take out a 33. When we take out the 33, we are kind of dividing everything by 33, separately. For example, when you factor out 33 from 6x^36x3, you get 2x^32x3 since you are basically just dividing the 66 by 33. Doing the same for 3x^23x2 and 99, we get our answer:
3- 3(2x^3-x^2+3)3(2x3−x2+3)
Side Note: (this is to help for future questions)
If we were just factoring 6x^3-3x^26x3−3x2, we would factor out 3x^23x2. This is because 3 is the largest common factor for the coefficients and both have x attached to them. But since the degree is not the same, we take the smaller degree of x so that both numbers can be divisible by it.
