How do you factor $8 x - 4$ $8x-4$ ?

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Answer 1 · 2017-01-22T02:49:09

See the entire factoring process below:

We can rewrite this expression as:

$(4 \times 2) x - (4 \times 1)$ $(4 xx 2)x - (4 xx 1)$

We can now factor out the $4$ $4$ term:

$4 (2 x - 1)$ $4(2x - 1)$

How do you factor 8x−48x-4?