How do you factor and simplify $4sin^2y+8siny+4$ ?

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Answer 1 · 2016-09-04T16:45:50

$4 (sin(y) + 1)^(2)$

We have: $4 sin^(2)(y) + 8 sin(y) + 4$

This expression can be factorised using the middle-term break:

$= 4 sin^(2)(y) + 4 sin(y) + 4 sin(y) + 4$

$= 4 sin(y) (sin(y) + 1) + 4 (sin(y) + 1)$

$= (sin(y) + 1) (4 sin(y) + 4)$

We can simplify this expression further by factoring out a $4$ in the second set of parentheses:

$= (sin(y) + 1) (4 (sin(y) + 1))$

$= 4 (sin(y) + 1) (sin(y) + 1)$

$= 4 (sin(y) + 1)^(2)$

How do you factor and simplify 4sin^2y+8siny+44sin^2y+8siny+4?