How do you factor $pβ - πp + 15pR^3$ ?

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Answer 1 · 2016-07-18T21:21:22

$p(β - π + 15R^3 )$

No matter how strange an expression looks, the symbols are just variables.
Always look for a common factor first: In this case "p"

$pβ - πp + 15pR^3 " HCF =p"$

= $p(β - π + 15R^3 )$

How do you factor pβ - πp + 15pR^3pβ - πp + 15pR^3?