How do you factor the monomial $121 a b c^{3}$ $121abc^3$ completely?

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Answer 1 · 2017-05-19T09:34:04

$121 a b c^{2} = 11 \times 11 \times a \times b \times c \times c$ $121abc^2=11xx11xxaxxbxxcxxc$

We know that $121 a b c^{3}$ $121abc^3$ is nothing but $121 \times a \times b \times c^{2}$ $121xxaxxbxxc^2$

i.e. $121 \times a \times b \times c \times c$ $121xxaxxbxxcxxc$

Hence to factor given monomial, one just needs to factorize $121$ $121$ and as $121 = 11 \times 11$ $121=11xx11$

$121 a b c^{2} = 11 \times 11 \times a \times b \times c \times c$ $121abc^2=11xx11xxaxxbxxcxxc$

How do you factor the monomial 121abc3121abc^3 completely?