How do you factor the monomial $12 g^{2} h^{4}$ $12g^2h^4$ completely?

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Answer 1 · 2017-02-03T14:30:08

$12 g^{2} h^{4} = 2 \times 2 \times 3 \times g \times g \times h \times h \times h \times h$ $12g^2h^4 = 2xx2xx3xxgxxgxxhxxhxxhxxh$

It is a bit unusual to factor a monomial, especially one that is in the simplest form.

You can write it in expanded form, showing it as the product of its prime factors:

$12 g^{2} h^{4} = 2 \times 2 \times 3 \times g \times g \times h \times h \times h \times h$ $12g^2h^4 = 2xx2xx3xxgxxgxxhxxhxxhxxh$

How do you factor the monomial 12g2h412g^2h^4 completely?