How do you factor the monomial $81n^5p$ completely?

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Answer 1 · 2017-07-05T20:15:18

To factor a monomial you factor constants to their primes and variables to single variable terms:

$81n^5p = 3 xx 3 xx 3 xx 3 xx n xx n xx n xx n xx n xx p$

How do you factor the monomial 81n^5p81n^5p completely?