How do you factor $x^ { 2} + 8x - 6x - 48$ ?

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Answer 1 · 2018-03-05T14:57:52

See a solution process below:

First, combine like terms:

$x^2 + (8 - 6)x - 48 =>$

$x^2 + 2x - 48$

Now, factor as:

$(x + 8)(x - 6)$

How do you factor x^ { 2} + 8x - 6x - 48x^ { 2} + 8x - 6x - 48?