How do you factor x^3-2x^2-3xx3−2x2−3x?

1 Answer
Max G.
May 9, 2017

x(x-3)(x+1)x(x−3)(x+1)

Explanation:

x(x^2 - 2x - 3)x(x2−2x−3)
Quadratic equation
x = (2+-sqrt(2^2 - 4(1)(-3)))/(2(1))x=2±√22−4(1)(−3)2(1)
x = (2+-4)/(2)x=2±42
x = 3 or -1x=3or−1
Zeroes for these values are:
(x-3)(x+1)(x−3)(x+1)
Add back the X taken out at the beginning:
x(x-3)(x+1)x(x−3)(x+1)
Hope this helps!

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