How do you factor $x^{4} + 27 x$ $x^4 + 27x$ ?

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How do you factor $x^{4} + 27 x$ $x^4 + 27x$ ?

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Answer 1 · 2016-07-24T19:42:16

$= x (x + 3) (x^{2} - 3 x + 9)$ $=x(x+3)(x^2-3x+9)$

Explanation:

$x^{4} + 27 x$ $x^4+27x$
$= x (x^{3} + 27)$ $=x(x^3+27)$
$= x (x^{3} + 3^{3})$ $=x(x^3+3^3)$
As per formula $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ $a^3+b^3=(a+b)(a^2-ab+b^2)$
we can write
$= x (x + 3) (x^{2} - 3 x + 3^{2})$ $=x(x+3)(x^2-3x+3^2)$
$= x (x + 3) (x^{2} - 3 x + 9)$ $=x(x+3)(x^2-3x+9)$

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How do you factor $x^{4} + 27 x$ $x^4 + 27x$ ?

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