Question

How do you factor: #y= 125x^3 - 8 #?

Answer 1

`y=(5x-2)(25x^2+10x+4)`

Explanation:

`y=125x^3-8`
or
`y=(5x)^3-(2)^3`

Since `a^3-b^3-(a-b)(a^2+ab+b^2)`
above equation can be written as

`y=(5x-2)((5x)^2+(5x)(2)+(2)^2)`
or
`y=(5x-2)(25x^2+10x+4)`