How do you factor: $y= 125x^3 - 8$ ?

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Answer 1 · 2016-07-26T09:26:36

$y=(5x-2)(25x^2+10x+4)$

$y=125x^3-8$
or
$y=(5x)^3-(2)^3$

Since $a^3-b^3-(a-b)(a^2+ab+b^2)$
above equation can be written as

$y=(5x-2)((5x)^2+(5x)(2)+(2)^2)$
or
$y=(5x-2)(25x^2+10x+4)$

How do you factor: y= 125x^3 - 8 y= 125x^3 - 8 ?