How do you factor $y = 3 x^{3} + 9 x^{2} + 4 x + 12$ $y= 3x^3 + 9x^2 + 4x + 12$ ?

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Answer 1 · 2016-07-03T16:09:50

$y = 3 x^{3} + 9 x^{2} + 4 x + 12 = (3 x^{2} + 4) (x + 3)$ $y=3x^3+9x^2+4x+12=(3x^2+4)(x+3)$

$y = 3 x^{3} + 9 x^{2} + 4 x + 12$ $y=3x^3+9x^2+4x+12$

= $3 x^{2} (x + 3) + 4 (x + 3)$ $3x^2(x+3)+4(x+3)$

= $(3 x^{2} + 4) (x + 3)$ $(3x^2+4)(x+3)$

How do you factor y=3x3+9x2+4x+12y= 3x^3 + 9x^2 + 4x + 12 ?