How do you factor $y= 4x^2 + 17x + 4$ ?

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Answer 1 · 2016-09-19T21:55:22

$4x^2+17x+4 = (4x+1)(x+4)$

Use an AC method:

Find a pair of factors of $AC = 4*4 = 16$ with sum $B = 17$

The pair $16, 1$ works, so use this to split the middle term, then factor by grouping:

$4x^2+17x+4 = (4x^2+16x)+(x+4)$

$color(white)(4x^2+17x+4) = 4x(x+4)+1(x+4)$

$color(white)(4x^2+17x+4) = (4x+1)(x+4)$

How do you factor y= 4x^2 + 17x + 4 y= 4x^2 + 17x + 4 ?