How do you factor $y = {(5 x + 2)}^{2} + 11 x (5 x + 2) + 30 ?$ $y= (5x+2)^2 + 11x(5x+2)+30?$ ?

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Answer 1 · 2018-03-26T05:08:35

$2 (40 x^{2} + 21 x + 17)$ $2(40x^2+21x+17)$

$(5 x + 2) (5 x + 2 + 11 x) + 30$ $(5x+2)(5x+2+11x)+30$

$(5 x + 2) (16 x + 2) + 30$ $(5x+2)(16x+2)+30$

$80 x^{2} + 42 x + 4 + 30$ $80x^2+42x+4+30$

$2 (40 x^{2} + 21 x + 17)$ $2(40x^2+21x+17)$

We could try to find the factors of this trinomial using the quadratic formula, however note that the discriminant is negative, namely

$21^{2} - 4 \cdot 40 \cdot 17 = - 2279$ $21^2-4*40*17= -2279$

So this is as far as this factors using real numbers.

How do you factor y= (5x+2)^2 + 11x(5x+2)+30?y=(5x+2)2+11x(5x+2)+30?y= (5x+2)^2 + 11x(5x+2)+30? ?