Question

How do you factor `y= 5x^2 + 22x + 8` ?

Answer 1

Ok write the quadratic using factors, you may try
`(5x+2)(x+4)`multiply out and test...
Key is to think of the quadratic as
`(ax+h)(x+k)` multiply long form

`ax^2+hx+akx+hk`
`ax^2+(h+ak)x+hk`

Now see `a = 5; h=2 ; k=4`
So tha h+ak = 2+20=22; and kh= 8
As required by your quadratic

Hope it was helpful, Yonas