How do you factor $y = 5 x^{3} - 20 x^{2} + 20 x$ $y= 5x^3 - 20x^2 +20x$ ?

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How do you factor $y = 5 x^{3} - 20 x^{2} + 20 x$ $y= 5x^3 - 20x^2 +20x$ ?

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Answer 1 · 2018-03-24T06:30:59

By taking x as common and then applying middle term splitting

Explanation:

First, take $x$ $x$ and $5$ $5$ as common:
$5 x^{3} - 20 x^{2} + 20 x$ $5x^3-20x^2+20x$
$= 5 x (x^{2} - 4 x + 4)$ $=5x(x^2-4x+4)$

Then by middle term splitting:
$= 5 x (x^{2} - 4 x + 4)$ $=5x(x^2-4x+4)$
$= 5 x (x^{2} - 2 x - 2 x + 4)$ $=5x(x^2-2x-2x+4)$
$= 5 x (x (x - 2) - 2 (x - 2))$ $=5x(x(x-2)-2(x-2))$
$= 5 x {(x - 2)}^{2}$ $=5x(x-2)^2$

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How do you factor $y = 5 x^{3} - 20 x^{2} + 20 x$ $y= 5x^3 - 20x^2 +20x$ ?

1 Answer

Explanation:

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How do you factor $y = 5 x^{3} - 20 x^{2} + 20 x$ $y= 5x^3 - 20x^2 +20x$ ?