How do you factor $y= 6x^2 + 12x – 48$ ?

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Answer 1 · 2016-02-19T04:43:16

see below

$6x^2+12x-48$
= $6(x^2+2x-8)$
= $6(x^2+4x-2x-8)$
= $6{x(x+4)-2(x+4)}$
= $6(x+4)(x-2)$

How do you factor y= 6x^2 + 12x – 48y= 6x^2 + 12x – 48 ?