How do you factor: $y = s^{2} - 8 s + 7$ $y= s^2-8s+7$ ?

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How do you factor: $y = s^{2} - 8 s + 7$ $y= s^2-8s+7$ ?

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Answer 1 · 2018-06-22T15:01:55

$y = s^{2} - 8 x + 7 \Leftrightarrow y = (s - 7) (s - 1)$ $y=s^2-8x+7hArrcolor(blue)(y=(s-7)(s-1))$

Explanation:

Since $(s + a) (s + b) = s^{2} + (a + b) s + a b$ $(s+a)(s+b)=s^2+(a+b)s+ab$
we are looking for constants $a$ $a$ and $b$ $b$
such that $a \times b = + 7$ $a xx b=+7$
and $(a + b) = - 8$ $(a+b)=-8$

Answer 2 · 2018-06-22T15:02:35

The same processes as when you use $x$ $x$

$y = (s - 1) (s - 8)$ $y=(s-1)(s-8)$

Explanation:

Note that $1 \times 7 = 7 and 1 + 7 = 8$ $1xx7=7 and 1+7=8$

but we need negative 8 so we use

$(- 1) \times (- 7) = + 7 and (- 1) + (- 7) = - 8$ $(-1)xx(-7)=+7 and (-1)+(-7)=-8$ as required

Thus $y = (s - 1) (s - 8)$ $y=(s-1)(s-8)$

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How do you factor: $y = s^{2} - 8 s + 7$ $y= s^2-8s+7$ ?

2 Answers

Explanation:

Explanation:

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How do you factor: $y = s^{2} - 8 s + 7$ $y= s^2-8s+7$ ?