How do you factor $y=x^2 + 4x - 5$ ?

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Answer 1 · 2016-03-18T19:07:50

If you mean to write it as a parabola in the form $y=a*(x-h)^2+k$

we have that

$y=(x^2+4x+4)-9=(x+2)^2-9$

If you mean to factor the LHS it is as follows

$y=x^2 + 4x - 5=>y=x^2+4x-4-1=> y=(x^2-1)+4(x-1)=> y=(x-1)(x+1)+4(x-1)=> y=(x-1)*(x+5)$

The graph of $y$ is

enter image source here

How do you factor y=x^2 + 4x - 5 y=x^2 + 4x - 5 ?