How do you factor $y = x^{2} - 6 x + 5$ $y= x^2-6x+5$ ?

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How do you factor $y = x^{2} - 6 x + 5$ $y= x^2-6x+5$ ?

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Answer 1 · 2016-05-17T16:37:03

Factors are $y = (x - 1) (x - 5)$ $y=(x-1)(x-5)$

Explanation:

If you have a quadratic function $a x^{2} + b x + c$ $ax^2+bx+c$ , to factorise it you should identify two numbers whose product is $a c$ $ac$ and sum is $b$ $b$ .

Here in $y = x^{2} - 6 x + 5$ $y=x^2-6x+5$ , we should identify two numbers whose product is $5$ $5$ and sum is $- 6$ $-6$ .

Such numbers are $- 5$ $-5$ and $- 1$ $-1$ and now splitting middle term into these we get $y = x^{2} - 5 x - x + 5$ $y=x^2-5x-x+5$ or

$y = x (x - 5) - 1 (x - 5) = (x - 1) (x - 5)$ $y=x(x-5)-1(x-5)=(x-1)(x-5)$ .

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How do you factor $y = x^{2} - 6 x + 5$ $y= x^2-6x+5$ ?

1 Answer

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Science

Math

Humanities

... and beyond

How do you factor y= x^2-6x+5y=x2−6x+5y= x^2-6x+5 ?

1 Answer

Explanation:

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How do you factor $y = x^{2} - 6 x + 5$ $y= x^2-6x+5$ ?