How do you factor: $y = x^{3} + 64$ $y= x^3 + 64$ ?

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How do you factor: $y = x^{3} + 64$ $y= x^3 + 64$ ?

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Answer 1 · 2015-12-30T11:55:06

$y = (x + 4) \cdot (x^{2} - 4 x + 16)$ $y = (x+4)*(x^2 -4x +16)$ .
(It's still possible to factorize the second degree polynomial, with complex numbers as roots)

Explanation:

Remember the rule $a^{3} + b^{3} = (a + b) \cdot (a^{2} - a b + b^{2})$ $a^3+b^3 = (a+b)*(a^2-ab+b^2)$ . In the case, $b^{3} = 64$ $b^3 = 64$ so $b = 4$ $b = 4$ .

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How do you factor: $y = x^{3} + 64$ $y= x^3 + 64$ ?

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How do you factor: $y = x^{3} + 64$ $y= x^3 + 64$ ?