How do you factor y=x^3 + 6x^2 - 4x - 24 y=x3+6x2−4x−24 ?

2 Answers
iceman
Dec 16, 2015

y=(x+6)(x-2)(x+2)y=(x+6)(x−2)(x+2)

Explanation:

y=x^3+6x^2-4x-24y=x3+6x2−4x−24 => factor by grouping:
y=x^2(x+6)-4(x+6)y=x2(x+6)−4(x+6)
y=(x +6)(x^2-4)y=(x+6)(x2−4) => use difference of squares:
y=(x+6)(x-2)(x+2)y=(x+6)(x−2)(x+2)

Johnson Z.
Dec 16, 2015

y=(x+2)(x-2)(x+6)y=(x+2)(x−2)(x+6)

Explanation:

y=x^3+6x^2-4x-24y=x3+6x2−4x−24

y=x^2(x+6)-4(x+6)y=x2(x+6)−4(x+6)

y=(x^2-4)(x+6)y=(x2−4)(x+6)

y=(x+2)(x-2)(x+6)y=(x+2)(x−2)(x+6)

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