How do you factor $y = (x - 5) {(x + 6)}^{2} - {(x - 5)}^{2} (x + 6)$ $y= (x-5)(x+6)^2 - (x-5)^2 (x+6)$ ?

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How do you factor $y = (x - 5) {(x + 6)}^{2} - {(x - 5)}^{2} (x + 6)$ $y= (x-5)(x+6)^2 - (x-5)^2 (x+6)$ ?

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Answer 1 · 2018-07-04T01:18:20

$y = (x - 5) (x + 6) (11)$ $y=(x-5)(x+6)(11)$

Explanation:

When factorising, you want to take out anything that you can find in both parts of the equation ie in $(x - 5) {(x + 6)}^{2}$ $(x-5)(x+6)^2$ and ${(x - 5)}^{2} (x + 6)$ $(x-5)^2(x+6)$

Hopefully, you will notice that there is one $x - 5$ $x-5$ and one $x + 6$ $x+6$ in both parts

Therefore, you can "take" them out
$y = (x - 5) (x + 6) (x + 6 - (x - 5))$ $y=(x-5)(x+6)(x+6-(x-5))$
$y = (x - 5) (x + 6) (x + 6 - x + 5)$ $y=(x-5)(x+6)(x+6-x+5)$
$y = (x - 5) (x + 6) (11)$ $y=(x-5)(x+6)(11)$

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How do you factor $y = (x - 5) {(x + 6)}^{2} - {(x - 5)}^{2} (x + 6)$ $y= (x-5)(x+6)^2 - (x-5)^2 (x+6)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you factor y= (x-5)(x+6)^2 - (x-5)^2 (x+6) y=(x−5)(x+6)2−(x−5)2(x+6)y= (x-5)(x+6)^2 - (x-5)^2 (x+6) ?

1 Answer

Explanation:

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How do you factor $y = (x - 5) {(x + 6)}^{2} - {(x - 5)}^{2} (x + 6)$ $y= (x-5)(x+6)^2 - (x-5)^2 (x+6)$ ?