How do you find $2 A - 3 B$ $2A-3B$ given $A=((-1, 0, 2, 2, ))$ and $B=((4, 0, -1, -2))$ ?

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Answer 1 · 2016-04-18T15:22:22

( $-$ 14 0 7 10 )

2 A = ( $-2$ 0 4 4 )

3 B = ( 12 0 $-3$ $-6$ )

Subtracting,

$2 A-3 B$ = ( $-14$ 0 7 10 )

How do you find 2A-3B2A−3B2A-3B given A=((-1, 0, 2, 2, ))A=((-1, 0, 2, 2, )) and B=((4, 0, -1, -2))B=((4, 0, -1, -2))?