How do you find $2 A - 3 B$ $2A-3B$ given $A=((5, -2, 3, 1))$ and $B=((-2, 3, 1, 0))$ ?

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Answer 1 · 2016-03-06T03:14:50

$2A-3B = ((16,-13,3,2))$

$2A = ((10,-4,6,2))$

$3B = ((-6,9,3,0))$

$2A-3B = ((16,-13,3,2))$

How do you find 2A-3B2A−3B2A-3B given A=((5, -2, 3, 1))A=((5, -2, 3, 1)) and B=((-2, 3, 1, 0))B=((-2, 3, 1, 0))?